What are the solutions to the equation -x^3+3x^2-3x+1=0 ?

The solutions to the equation -x^3+3x^2-3x+1=0 are x=1

Find the zeros of -x^3+3x^2-3x+1=0

The zeros of -x^3+3x^2-3x+1=0 are x=1

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- x^{3} + 3 x^{2} - 3 x + 1 = 0

x = 1

Solution steps

- x^{3} + 3 x^{2} - 3 x + 1 = 0

Factor

- x^{3} + 3 x^{2} - 3 x + 1 : - (x - 1)^{3}

- (x - 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0

Solve

x - 1 = 0 : x = 1

The solution is

x = 1

5 x^{4} - 80 x^{2} = 0

4 x^{3} - 2 x = 0

x^{4} - 7 x^{2} - 18 = 0

x^{3} - 2 x - 2 = 0

6 x^{3} + 5 x^{2} - 4 x = 0

What are the solutions to the equation -x^3+3x^2-3x+1=0 ?
The solutions to the equation -x^3+3x^2-3x+1=0 are x=1
Find the zeros of -x^3+3x^2-3x+1=0
The zeros of -x^3+3x^2-3x+1=0 are x=1