What are the solutions to the equation x^3+2x^2+4x+8=0 ?

The solutions to the equation x^3+2x^2+4x+8=0 are x=-2,x=2i,x=-2i

Find the zeros of x^3+2x^2+4x+8=0

The zeros of x^3+2x^2+4x+8=0 are x=-2,x=2i,x=-2i

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x^{3} + 2 x^{2} + 4 x + 8 = 0

x = - 2, x = 2 i, x = - 2 i

Solution steps

x^{3} + 2 x^{2} + 4 x + 8 = 0

Factor

x^{3} + 2 x^{2} + 4 x + 8 : (x + 2) (x^{2} + 4)

(x + 2) (x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = - 2, x = 2 i, x = - 2 i

x^{5} + 1 = 0

x^{3} + 2 x^{2} + x - 2 = 0

3 x^{3} - 12 x = 0

x^{4} - 3 x^{3} - 2 x^{2} + 10 x - 12 = 0

(x - 1)^{2} (x + 2) = 0

What are the solutions to the equation x^3+2x^2+4x+8=0 ?
The solutions to the equation x^3+2x^2+4x+8=0 are x=-2,x=2i,x=-2i
Find the zeros of x^3+2x^2+4x+8=0
The zeros of x^3+2x^2+4x+8=0 are x=-2,x=2i,x=-2i