What are the solutions to the equation -x^3+6x^2-12x+8=0 ?

The solutions to the equation -x^3+6x^2-12x+8=0 are x=2

Find the zeros of -x^3+6x^2-12x+8=0

The zeros of -x^3+6x^2-12x+8=0 are x=2

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- x^{3} + 6 x^{2} - 12 x + 8 = 0

x = 2

Solution steps

- x^{3} + 6 x^{2} - 12 x + 8 = 0

Factor

- x^{3} + 6 x^{2} - 12 x + 8 : - (x - 2)^{3}

- (x - 2)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0

Solve

x - 2 = 0 : x = 2

The solution is

x = 2

x^{4} - 9 x^{2} + 18 = 0

x^{3} + x^{2} - 8 x - 12 = 0

y^{3} + 4 = 120

2 x = 16 x^{4}

2 x^{3} + 1 = x^{2} + 2

What are the solutions to the equation -x^3+6x^2-12x+8=0 ?
The solutions to the equation -x^3+6x^2-12x+8=0 are x=2
Find the zeros of -x^3+6x^2-12x+8=0
The zeros of -x^3+6x^2-12x+8=0 are x=2