What are the solutions to the equation x(x-2)(x+3)(x-12)=0 ?

The solutions to the equation x(x-2)(x+3)(x-12)=0 are x=0,x=2,x=-3,x=12

Find the zeros of x(x-2)(x+3)(x-12)=0

The zeros of x(x-2)(x+3)(x-12)=0 are x=0,x=2,x=-3,x=12

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x (x - 2) (x + 3) (x - 12) = 0

x = 0, x = 2, x = - 3, x = 12

Solution steps

x (x - 2) (x + 3) (x - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x + 3 = 0 or x - 12 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 12 = 0 : x = 12

The solutions are

x = 0, x = 2, x = - 3, x = 12

(x^{2} + 3 x + 2)^{2} - 8 (x^{2} + 3 x) = 4

x^{6} + 72 x^{3} + 512 = 0

x^{3} - 4 x^{2} = 0

x^{3} = 3 x

4 x - 4 x^{3} = 0

What are the solutions to the equation x(x-2)(x+3)(x-12)=0 ?
The solutions to the equation x(x-2)(x+3)(x-12)=0 are x=0,x=2,x=-3,x=12
Find the zeros of x(x-2)(x+3)(x-12)=0
The zeros of x(x-2)(x+3)(x-12)=0 are x=0,x=2,x=-3,x=12