What are the solutions to the equation 3x^3-19x^2-14x=0 ?

The solutions to the equation 3x^3-19x^2-14x=0 are x=0,x=-2/3 ,x=7

Find the zeros of 3x^3-19x^2-14x=0

The zeros of 3x^3-19x^2-14x=0 are x=0,x=-2/3 ,x=7

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3 x^{3} - 19 x^{2} - 14 x = 0

x = 0, x = - \frac{2}{3}, x = 7

Decimal Notation

x = 0, x = - 0.66666 \dots, x = 7

Solution steps

3 x^{3} - 19 x^{2} - 14 x = 0

Factor

3 x^{3} - 19 x^{2} - 14 x : x (3 x + 2) (x - 7)

x (3 x + 2) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 2 = 0 or x - 7 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

x - 7 = 0 : x = 7

The solutions are

x = 0, x = - \frac{2}{3}, x = 7

15 x^{4} - 15 = 0

x^{3} + 4 x^{2} + 4 x = 0

x (x - 1) (x + 2) = 0

2 x - 3 = 8 x^{3} - 12 x^{2}

36 x^{4} - 13 x^{2} + 1 = 0

What are the solutions to the equation 3x^3-19x^2-14x=0 ?
The solutions to the equation 3x^3-19x^2-14x=0 are x=0,x=-2/3 ,x=7
Find the zeros of 3x^3-19x^2-14x=0
The zeros of 3x^3-19x^2-14x=0 are x=0,x=-2/3 ,x=7