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What are the solutions to the equation x^4-22x^2+96=0 ?
The solutions to the equation x^4-22x^2+96=0 are x=4,x=-4,x=sqrt(6),x=-sqrt(6)Find the zeros of x^4-22x^2+96=0
The zeros of x^4-22x^2+96=0 are x=4,x=-4,x=sqrt(6),x=-sqrt(6)