What are the solutions to the equation 0=x^3-4x^2-9x+36 ?

The solutions to the equation 0=x^3-4x^2-9x+36 are x=4,x=-3,x=3

Find the zeros of 0=x^3-4x^2-9x+36

The zeros of 0=x^3-4x^2-9x+36 are x=4,x=-3,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{3} - 4 x^{2} - 9 x + 36

x = 4, x = - 3, x = 3

Solution steps

0 = x^{3} - 4 x^{2} - 9 x + 36

Switch sides

x^{3} - 4 x^{2} - 9 x + 36 = 0

Factor

x^{3} - 4 x^{2} - 9 x + 36 : (x - 4) (x + 3) (x - 3)

(x - 4) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 4, x = - 3, x = 3

3^{10} = 3^{7} \cdot x^{3}

x^{3} + 4 x^{2} - 4 x - 16 = 0

x^{3} + 2 x^{2} - 16 x - 32 = 0

x^{3} = - 512

x^{4} + 64 = 0

What are the solutions to the equation 0=x^3-4x^2-9x+36 ?
The solutions to the equation 0=x^3-4x^2-9x+36 are x=4,x=-3,x=3
Find the zeros of 0=x^3-4x^2-9x+36
The zeros of 0=x^3-4x^2-9x+36 are x=4,x=-3,x=3