What are the solutions to the equation 7t^3+2t^2-t=0 ?

The solutions to the equation 7t^3+2t^2-t=0 are t=0,t=(-1+2sqrt(2))/7 ,t=-(1+2sqrt(2))/7

Find the zeros of 7t^3+2t^2-t=0

The zeros of 7t^3+2t^2-t=0 are t=0,t=(-1+2sqrt(2))/7 ,t=-(1+2sqrt(2))/7

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7 t^{3} + 2 t^{2} - t = 0

t = 0, t = \frac{- 1 + 2 2}{7}, t = - \frac{1 + 2 2}{7}

Decimal Notation

t = 0, t = 0.26120 \dots, t = - 0.54691 \dots

Solution steps

7 t^{3} + 2 t^{2} - t = 0

Factor

7 t^{3} + 2 t^{2} - t : t (7 t^{2} + 2 t - 1)

t (7 t^{2} + 2 t - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or 7 t^{2} + 2 t - 1 = 0

Solve

7 t^{2} + 2 t - 1 = 0 : t = \frac{- 1 + 2 2}{7}, t = - \frac{1 + 2 2}{7}

The solutions are

t = 0, t = \frac{- 1 + 2 2}{7}, t = - \frac{1 + 2 2}{7}

12 x^{3} + 12 x^{2} - 24 x = 0

x^{3} + 5.4 x^{2} - 52.1 = 0

x^{3} - 15 x^{2} + 50 x = 0

(x + 1)^{4} = 16 (x - 1)^{4}

2 x^{5} - 243 = 0

What are the solutions to the equation 7t^3+2t^2-t=0 ?
The solutions to the equation 7t^3+2t^2-t=0 are t=0,t=(-1+2sqrt(2))/7 ,t=-(1+2sqrt(2))/7
Find the zeros of 7t^3+2t^2-t=0
The zeros of 7t^3+2t^2-t=0 are t=0,t=(-1+2sqrt(2))/7 ,t=-(1+2sqrt(2))/7