What are the solutions to the equation x^4+6x^3-33x^2-46x+72=0 ?

The solutions to the equation x^4+6x^3-33x^2-46x+72=0 are x=1,x=-2,x=4,x=-9

Find the zeros of x^4+6x^3-33x^2-46x+72=0

The zeros of x^4+6x^3-33x^2-46x+72=0 are x=1,x=-2,x=4,x=-9

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x^{4} + 6 x^{3} - 33 x^{2} - 46 x + 72 = 0

x = 1, x = - 2, x = 4, x = - 9

Solution steps

x^{4} + 6 x^{3} - 33 x^{2} - 46 x + 72 = 0

Factor

x^{4} + 6 x^{3} - 33 x^{2} - 46 x + 72 : (x - 1) (x + 2) (x - 4) (x + 9)

(x - 1) (x + 2) (x - 4) (x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x - 4 = 0 or x + 9 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

Solve

x + 9 = 0 : x = - 9

The solutions are

x = 1, x = - 2, x = 4, x = - 9

x^{3} - 4 x^{2} + 6 x - 4 = 0

x^{3} - 2 x^{2} - 5 x + 10 = 0

x^{3} + 4 x^{2} - 16 x - 64 = 0

x^{6} - 72 x^{3} + 512 = 0

27 x = 3 x^{3}

What are the solutions to the equation x^4+6x^3-33x^2-46x+72=0 ?
The solutions to the equation x^4+6x^3-33x^2-46x+72=0 are x=1,x=-2,x=4,x=-9
Find the zeros of x^4+6x^3-33x^2-46x+72=0
The zeros of x^4+6x^3-33x^2-46x+72=0 are x=1,x=-2,x=4,x=-9