What are the solutions to the equation (u^2+8u+7)(5u-40)=0 ?

The solutions to the equation (u^2+8u+7)(5u-40)=0 are u=-1,u=-7,u=8

Find the zeros of (u^2+8u+7)(5u-40)=0

The zeros of (u^2+8u+7)(5u-40)=0 are u=-1,u=-7,u=8

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(u^{2} + 8 u + 7) (5 u - 40) = 0

u = - 1, u = - 7, u = 8

Solution steps

(u^{2} + 8 u + 7) (5 u - 40) = 0

Factor

(u^{2} + 8 u + 7) (5 u - 40) : 5 (u + 1) (u + 7) (u - 8)

5 (u + 1) (u + 7) (u - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

u + 1 = 0 or u + 7 = 0 or u - 8 = 0

Solve

u + 1 = 0 : u = - 1

Solve

u + 7 = 0 : u = - 7

Solve

u - 8 = 0 : u = 8

The solutions are

u = - 1, u = - 7, u = 8

x^{3} - 2 x^{2} - 8 x = 0

x^{3} + 4 x^{2} + 3 x = 0

x^{6} + 35 x^{3} + 216 = 0

3 x^{3} + 5 x - 11 = 0

- x^{3} = 25 x

What are the solutions to the equation (u^2+8u+7)(5u-40)=0 ?
The solutions to the equation (u^2+8u+7)(5u-40)=0 are u=-1,u=-7,u=8
Find the zeros of (u^2+8u+7)(5u-40)=0
The zeros of (u^2+8u+7)(5u-40)=0 are u=-1,u=-7,u=8