What are the solutions to the equation 2(x-3(x-4(x-(x^8+1))))=1 ?

The solutions to the equation 2(x-3(x-4(x-(x^8+1))))=1 are No Solution for x\in\mathbb{R}

Find the zeros of 2(x-3(x-4(x-(x^8+1))))=1

The zeros of 2(x-3(x-4(x-(x^8+1))))=1 are No Solution for x\in\mathbb{R}

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2 (x - 3 (x - 4 (x - (x^{8} + 1)))) = 1

No Solution for x \in R

Solution steps

2 (x - 3 (x - 4 (x - (x^{8} + 1)))) = 1

Expand

2 (x - 3 (x - 4 (x - (x^{8} + 1)))) : 20 x - 24 x^{8} - 24

20 x - 24 x^{8} - 24 = 1

Move

1

to the left side

- 24 x^{8} + 20 x - 25 = 0

Find one solution for

- 24 x^{8} + 20 x - 25 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

x^{3} = \frac{8}{125}

x^{6} - 4 x^{3} - 5 = 0

2 x^{3} + 12 = x^{2} - 13

4 x^{3} - 36 x = 0

(30 x^{3}) - (15 + 7) = m

What are the solutions to the equation 2(x-3(x-4(x-(x^8+1))))=1 ?
The solutions to the equation 2(x-3(x-4(x-(x^8+1))))=1 are No Solution for x\in\mathbb{R}
Find the zeros of 2(x-3(x-4(x-(x^8+1))))=1
The zeros of 2(x-3(x-4(x-(x^8+1))))=1 are No Solution for x\in\mathbb{R}