What are the solutions to the equation solvefor x,x^3+mx^2-x-m=0 ?

The solutions to the equation solvefor x,x^3+mx^2-x-m=0 are x=-m,x=-1,x=1

Find the zeros of solvefor x,x^3+mx^2-x-m=0

The zeros of solvefor x,x^3+mx^2-x-m=0 are x=-m,x=-1,x=1

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solve for

x, x^{3} + m x^{2} - x - m = 0

x = - m, x = - 1, x = 1

Solution steps

x^{3} + m x^{2} - x - m = 0

Factor

x^{3} + m x^{2} - x - m : (x + m) (x + 1) (x - 1)

(x + m) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + m = 0 or x + 1 = 0 or x - 1 = 0

Solve

x + m = 0 : x = - m

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - m, x = - 1, x = 1

2 x^{3} + 3 x^{2} - 11 x - 6 = 0

8 x^{3} - 16 x^{2} = 0

x^{3} - 3 x^{2} + 4 x - 12 = 0

x^{3} + 2 x^{2} - 42 = 0

(n - 1)^{3} + n^{3} = (n + 1)^{3}

What are the solutions to the equation solvefor x,x^3+mx^2-x-m=0 ?
The solutions to the equation solvefor x,x^3+mx^2-x-m=0 are x=-m,x=-1,x=1
Find the zeros of solvefor x,x^3+mx^2-x-m=0
The zeros of solvefor x,x^3+mx^2-x-m=0 are x=-m,x=-1,x=1