What are the solutions to the equation (3-x)(x^2+15)=0 ?

The solutions to the equation (3-x)(x^2+15)=0 are x=3,x=sqrt(15)i,x=-sqrt(15)i

Find the zeros of (3-x)(x^2+15)=0

The zeros of (3-x)(x^2+15)=0 are x=3,x=sqrt(15)i,x=-sqrt(15)i

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(3 - x) (x^{2} + 15) = 0

x = 3, x = 15 i, x = - 15 i

Solution steps

(3 - x) (x^{2} + 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 - x = 0 or x^{2} + 15 = 0

Solve

3 - x = 0 : x = 3

Solve

x^{2} + 15 = 0 : x = 15 i, x = - 15 i

The solutions are

x = 3, x = 15 i, x = - 15 i

x^{3} + 6 x^{2} - 36 x - 216 = 0

m^{3} = 343

x^{3} - x^{2} + x - 1 = x^{2} + 1

0 = 2 x^{7} + 3 x^{5} - 9 x^{2} + 6

3 x^{3} + 15 x^{2} - 2 x - 10 = 0

What are the solutions to the equation (3-x)(x^2+15)=0 ?
The solutions to the equation (3-x)(x^2+15)=0 are x=3,x=sqrt(15)i,x=-sqrt(15)i
Find the zeros of (3-x)(x^2+15)=0
The zeros of (3-x)(x^2+15)=0 are x=3,x=sqrt(15)i,x=-sqrt(15)i