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What are the solutions to the equation x^4-19x^2+48=0 ?
The solutions to the equation x^4-19x^2+48=0 are x=4,x=-4,x=sqrt(3),x=-sqrt(3)Find the zeros of x^4-19x^2+48=0
The zeros of x^4-19x^2+48=0 are x=4,x=-4,x=sqrt(3),x=-sqrt(3)