What are the solutions to the equation r^3=125 ?

The solutions to the equation r^3=125 are r=5,r=-5/2+(5sqrt(3))/2 i,r=-5/2-(5sqrt(3))/2 i

Find the zeros of r^3=125

The zeros of r^3=125 are r=5,r=-5/2+(5sqrt(3))/2 i,r=-5/2-(5sqrt(3))/2 i

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r^{3} = 125

r = 5, r = - \frac{5}{2} + \frac{5 3}{2} i, r = - \frac{5}{2} - \frac{5 3}{2} i

Solution steps

r^{3} = 125

For

x^{3} = f (a)

the solutions are

Simplify

r = 5, r = - \frac{5}{2} + \frac{5 3}{2} i, r = - \frac{5}{2} - \frac{5 3}{2} i

x^{9} = 1 2^{2} \cdot 1 2^{7}

x^{3} + 4 x^{2} + 9 x + 36 = 0

x, y = 3 x^{3} + 7

3 x^{3} - 4 x^{2} - 5 x + 2 = 0

x^{3} + x^{2} - 4 x + 6 = 0

What are the solutions to the equation r^3=125 ?
The solutions to the equation r^3=125 are r=5,r=-5/2+(5sqrt(3))/2 i,r=-5/2-(5sqrt(3))/2 i
Find the zeros of r^3=125
The zeros of r^3=125 are r=5,r=-5/2+(5sqrt(3))/2 i,r=-5/2-(5sqrt(3))/2 i