What are the solutions to the equation 9x^2+3x+1=0 ?

The solutions to the equation 9x^2+3x+1=0 are x=-1/6+i(sqrt(3))/6 ,x=-1/6-i(sqrt(3))/6

Find the zeros of 9x^2+3x+1=0

The zeros of 9x^2+3x+1=0 are x=-1/6+i(sqrt(3))/6 ,x=-1/6-i(sqrt(3))/6

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9 x^{2} + 3 x + 1 = 0

x = - \frac{1}{6} + i \frac{3}{6}, x = - \frac{1}{6} - i \frac{3}{6}

Solution steps

9 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

Simplify

3^{2} - 4 \cdot 9 \cdot 1 : 33 i

x_{1, 2} = \frac{- 3 \pm 3 3 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 3 + 3 3 i}{2 \cdot 9}, x_{2} = \frac{- 3 - 3 3 i}{2 \cdot 9}

x = \frac{- 3 + 3 3 i}{2 \cdot 9} : - \frac{1}{6} + i \frac{3}{6}

x = \frac{- 3 - 3 3 i}{2 \cdot 9} : - \frac{1}{6} - i \frac{3}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{6} + i \frac{3}{6}, x = - \frac{1}{6} - i \frac{3}{6}

- 11 \geq \frac{c}{2}

a^{12} + b^{12}

23400

69 x^{2} + 2 x - 12 = - 12

863

What are the solutions to the equation 9x^2+3x+1=0 ?
The solutions to the equation 9x^2+3x+1=0 are x=-1/6+i(sqrt(3))/6 ,x=-1/6-i(sqrt(3))/6
Find the zeros of 9x^2+3x+1=0
The zeros of 9x^2+3x+1=0 are x=-1/6+i(sqrt(3))/6 ,x=-1/6-i(sqrt(3))/6