What are the solutions to the equation x^3=i ?

The solutions to the equation x^3=i are x=(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2+i 1/2 ,x=-i

Find the zeros of x^3=i

The zeros of x^3=i are x=(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2+i 1/2 ,x=-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} = i

x = \frac{3}{2} + i \frac{1}{2}, x = - \frac{3}{2} + i \frac{1}{2}, x = - i

Solution steps

x^{3} = i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 3, a = i

∣ a ∣ = 1

ar g (a) = \frac{π}{2}

Simplify

x = \frac{3}{2} + i \frac{1}{2}, x = - \frac{3}{2} + i \frac{1}{2}, x = - i

x^{3} + 3 x^{2} - 6 x - 8 = 0

2 x^{3} - 5 x^{2} - 10 x + 5 = 0

r^{4} - 1 = 3

x, 9 y^{2} = 4 x^{3}

- x^{3} + 8 x^{2} - 21 x + 18 = 0

What are the solutions to the equation x^3=i ?
The solutions to the equation x^3=i are x=(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2+i 1/2 ,x=-i
Find the zeros of x^3=i
The zeros of x^3=i are x=(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2+i 1/2 ,x=-i