What are the solutions to the equation x^3+4x^2-5x=-3x^2-5x ?

The solutions to the equation x^3+4x^2-5x=-3x^2-5x are x=0,x=-7

Find the zeros of x^3+4x^2-5x=-3x^2-5x

The zeros of x^3+4x^2-5x=-3x^2-5x are x=0,x=-7

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x^{3} + 4 x^{2} - 5 x = - 3 x^{2} - 5 x

x = 0, x = - 7

Solution steps

x^{3} + 4 x^{2} - 5 x = - 3 x^{2} - 5 x

Move

5 x

to the left side

x^{3} + 4 x^{2} = - 3 x^{2}

Move

3 x^{2}

to the left side

x^{3} + 7 x^{2} = 0

Factor

x^{3} + 7 x^{2} : x^{2} (x + 7)

x^{2} (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 7 = 0

Solve

x + 7 = 0 : x = - 7

The solutions are

x = 0, x = - 7

4 z^{4} - 2 z^{2} + 1 = 0

x^{4} - 36 = 0

x^{6} - 6 x^{3} - 7 = 0

x^{3} + 3 x^{2} - 9 x + 5 = 0

2 x^{4} - 7 x^{2} - 4 = 0

What are the solutions to the equation x^3+4x^2-5x=-3x^2-5x ?
The solutions to the equation x^3+4x^2-5x=-3x^2-5x are x=0,x=-7
Find the zeros of x^3+4x^2-5x=-3x^2-5x
The zeros of x^3+4x^2-5x=-3x^2-5x are x=0,x=-7