What are the solutions to the equation (x-1)(x+2)(x-3)=0 ?

The solutions to the equation (x-1)(x+2)(x-3)=0 are x=1,x=-2,x=3

Find the zeros of (x-1)(x+2)(x-3)=0

The zeros of (x-1)(x+2)(x-3)=0 are x=1,x=-2,x=3

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(x - 1) (x + 2) (x - 3) = 0

x = 1, x = - 2, x = 3

Solution steps

(x - 1) (x + 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = 1, x = - 2, x = 3

(z + 1)^{4} = (z - 1)^{4}

y^{3} = 125

y^{3} = \frac{27}{1000}

x^{3} + x = 9

z^{4} = (1 + 2 i)^{8}

What are the solutions to the equation (x-1)(x+2)(x-3)=0 ?
The solutions to the equation (x-1)(x+2)(x-3)=0 are x=1,x=-2,x=3
Find the zeros of (x-1)(x+2)(x-3)=0
The zeros of (x-1)(x+2)(x-3)=0 are x=1,x=-2,x=3