What are the solutions to the equation 0=x^3-x^2-3x+3 ?

The solutions to the equation 0=x^3-x^2-3x+3 are x=1,x=-sqrt(3),x=sqrt(3)

Find the zeros of 0=x^3-x^2-3x+3

The zeros of 0=x^3-x^2-3x+3 are x=1,x=-sqrt(3),x=sqrt(3)

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0 = x^{3} - x^{2} - 3 x + 3

x = 1, x = - 3, x = 3

Decimal Notation

x = 1, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

0 = x^{3} - x^{2} - 3 x + 3

Switch sides

x^{3} - x^{2} - 3 x + 3 = 0

Factor

x^{3} - x^{2} - 3 x + 3 : (x - 1) (x + 3) (x - 3)

(x - 1) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 1, x = - 3, x = 3

x^{4} + x = 0

z^{4} + 1 - i 3 = 0

3 x^{3} + x^{2} - 12 x - 4 = 0

x^{3} + 9 x = 0

36 x^{3} + 24 x^{2} - 4 x = 0

What are the solutions to the equation 0=x^3-x^2-3x+3 ?
The solutions to the equation 0=x^3-x^2-3x+3 are x=1,x=-sqrt(3),x=sqrt(3)
Find the zeros of 0=x^3-x^2-3x+3
The zeros of 0=x^3-x^2-3x+3 are x=1,x=-sqrt(3),x=sqrt(3)