What are the solutions to the equation (3x^2-10x+8)(2x-b)=0 ?

The solutions to the equation (3x^2-10x+8)(2x-b)=0 are x= 4/3 ,x=2,x= b/2

Find the zeros of (3x^2-10x+8)(2x-b)=0

The zeros of (3x^2-10x+8)(2x-b)=0 are x= 4/3 ,x=2,x= b/2

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(3 x^{2} - 10 x + 8) (2 x - b) = 0

x = \frac{4}{3}, x = 2, x = \frac{b}{2}

Solution steps

(3 x^{2} - 10 x + 8) (2 x - b) = 0

Factor

(3 x^{2} - 10 x + 8) (2 x - b) : (3 x - 4) (x - 2) (2 x - b)

(3 x - 4) (x - 2) (2 x - b) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 4 = 0 or x - 2 = 0 or 2 x - b = 0

Solve

3 x - 4 = 0 : x = \frac{4}{3}

Solve

x - 2 = 0 : x = 2

Solve

2 x - b = 0 : x = \frac{b}{2}

The solutions are

x = \frac{4}{3}, x = 2, x = \frac{b}{2}

3 (t^{2} - 9)^{2} + 16 (t^{2} - 9) = - 5

D, 2 b - hb = D^{3}

x^{3} - 6 x^{2} + x - 6 = x^{2} + 1

y (y - 5)^{3} - 14 (y - 5)^{2} = 0

b^{3} = 4

What are the solutions to the equation (3x^2-10x+8)(2x-b)=0 ?
The solutions to the equation (3x^2-10x+8)(2x-b)=0 are x= 4/3 ,x=2,x= b/2
Find the zeros of (3x^2-10x+8)(2x-b)=0
The zeros of (3x^2-10x+8)(2x-b)=0 are x= 4/3 ,x=2,x= b/2