What are the solutions to the equation x^3-15x+1=0 ?

The solutions to the equation x^3-15x+1=0 are x\approx 0.06668…,x\approx 3.83920…,x\approx-3.90589…

Find the zeros of x^3-15x+1=0

The zeros of x^3-15x+1=0 are x\approx 0.06668…,x\approx 3.83920…,x\approx-3.90589…

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x^{3} - 15 x + 1 = 0

x \approx 0.06668 \dots, x \approx 3.83920 \dots, x \approx - 3.90589 \dots

Solution steps

x^{3} - 15 x + 1 = 0

Find one solution for

x^{3} - 15 x + 1 = 0

using Newton-Raphson:

x \approx 0.06668 \dots

Apply long division:

\frac{x ^{3} - 15 x + 1}{x - 0.06668 \dots} = x^{2} + 0.06668 \dots x - 14.99555 \dots

x^{2} + 0.06668 \dots x - 14.99555 \dots \approx 0

Find one solution for

x^{2} + 0.06668 \dots x - 14.99555 \dots = 0

using Newton-Raphson:

x \approx 3.83920 \dots

Apply long division:

\frac{x ^{2} + 0.06668 \dots x - 14.99555 \dots}{x - 3.83920 \dots} = x + 3.90589 \dots

x + 3.90589 \dots \approx 0

x \approx - 3.90589 \dots

The solutions are

x \approx 0.06668 \dots, x \approx 3.83920 \dots, x \approx - 3.90589 \dots

x, x^{3} + y^{5} = 4

x^{3} + 3 x^{2} - 2 x - 5 = 0

m^{4} + 7 m^{2} + 6 = 0

4 x - x^{3} = 0

x^{4} - 3 x^{2} - 18 = 0

What are the solutions to the equation x^3-15x+1=0 ?
The solutions to the equation x^3-15x+1=0 are x\approx 0.06668…,x\approx 3.83920…,x\approx-3.90589…
Find the zeros of x^3-15x+1=0
The zeros of x^3-15x+1=0 are x\approx 0.06668…,x\approx 3.83920…,x\approx-3.90589…