What are the solutions to the equation -3x^2+6x+16=0 ?

The solutions to the equation -3x^2+6x+16=0 are x=-(-3+sqrt(57))/3 ,x=(3+sqrt(57))/3

Find the zeros of -3x^2+6x+16=0

The zeros of -3x^2+6x+16=0 are x=-(-3+sqrt(57))/3 ,x=(3+sqrt(57))/3

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- 3 x^{2} + 6 x + 16 = 0

x = - \frac{- 3 + 57}{3}, x = \frac{3 + 57}{3}

Decimal Notation

x = - 1.51661 \dots, x = 3.51661 \dots

Solution steps

- 3 x^{2} + 6 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 16}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 16 = 257

x_{1, 2} = \frac{- 6 \pm 2 57}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 57}{2 ( - 3 )}, x_{2} = \frac{- 6 - 2 57}{2 ( - 3 )}

x = \frac{- 6 + 2 57}{2 ( - 3 )} : - \frac{- 3 + 57}{3}

x = \frac{- 6 - 2 57}{2 ( - 3 )} : \frac{3 + 57}{3}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 57}{3}, x = \frac{3 + 57}{3}

\frac{162}{5} \cdot 2

\frac{n - 4}{n + 4} - \frac{( n - 1 ) - 4}{( n - 1 ) + 4}

72 = 0.049 (\frac{800}{0.2}) (\frac{v ^{2}}{2 \cdot 9.81})

7 k - 2 \geq - 9

3 ln (4)

What are the solutions to the equation -3x^2+6x+16=0 ?
The solutions to the equation -3x^2+6x+16=0 are x=-(-3+sqrt(57))/3 ,x=(3+sqrt(57))/3
Find the zeros of -3x^2+6x+16=0
The zeros of -3x^2+6x+16=0 are x=-(-3+sqrt(57))/3 ,x=(3+sqrt(57))/3