What are the solutions to the equation x^2(x+1)-64(x+1)=0 ?

The solutions to the equation x^2(x+1)-64(x+1)=0 are x=-1,x=-8,x=8

Find the zeros of x^2(x+1)-64(x+1)=0

The zeros of x^2(x+1)-64(x+1)=0 are x=-1,x=-8,x=8

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x^{2} (x + 1) - 64 (x + 1) = 0

x = - 1, x = - 8, x = 8

Solution steps

x^{2} (x + 1) - 64 (x + 1) = 0

Factor

x^{2} (x + 1) - 64 (x + 1) : (x + 1) (x + 8) (x - 8)

(x + 1) (x + 8) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 8 = 0 or x - 8 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 8 = 0 : x = - 8

Solve

x - 8 = 0 : x = 8

The solutions are

x = - 1, x = - 8, x = 8

x^{3} + 6 x^{2} = 16 x

x^{3} = 100

x^{3} = \frac{8}{27}

x^{3} + 4 x^{2} + 13 x = 0

z^{3} = 2

What are the solutions to the equation x^2(x+1)-64(x+1)=0 ?
The solutions to the equation x^2(x+1)-64(x+1)=0 are x=-1,x=-8,x=8
Find the zeros of x^2(x+1)-64(x+1)=0
The zeros of x^2(x+1)-64(x+1)=0 are x=-1,x=-8,x=8