What are the solutions to the equation 48x+4x^2-2x^3=0 ?

The solutions to the equation 48x+4x^2-2x^3=0 are x=0,x=-4,x=6

Find the zeros of 48x+4x^2-2x^3=0

The zeros of 48x+4x^2-2x^3=0 are x=0,x=-4,x=6

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48 x + 4 x^{2} - 2 x^{3} = 0

x = 0, x = - 4, x = 6

Solution steps

48 x + 4 x^{2} - 2 x^{3} = 0

Factor

48 x + 4 x^{2} - 2 x^{3} : - 2 x (x + 4) (x - 6)

- 2 x (x + 4) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 4 = 0 or x - 6 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 6 = 0 : x = 6

The solutions are

x = 0, x = - 4, x = 6

216 x = 6 x^{3}

x^{4} + x^{2} - 20 = 0

x^{3} + x^{2} - 25 x - 25 = 0

x^{3} + x^{2} - 3 x - 3 = 0

x^{3} - 5 x^{2} + 7 x - 3 = 0

What are the solutions to the equation 48x+4x^2-2x^3=0 ?
The solutions to the equation 48x+4x^2-2x^3=0 are x=0,x=-4,x=6
Find the zeros of 48x+4x^2-2x^3=0
The zeros of 48x+4x^2-2x^3=0 are x=0,x=-4,x=6