What are the solutions to the equation -x^3+10x^2-32x+32=0 ?

The solutions to the equation -x^3+10x^2-32x+32=0 are x=2,x=4

Find the zeros of -x^3+10x^2-32x+32=0

The zeros of -x^3+10x^2-32x+32=0 are x=2,x=4

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- x^{3} + 10 x^{2} - 32 x + 32 = 0

x = 2, x = 4

Solution steps

- x^{3} + 10 x^{2} - 32 x + 32 = 0

Factor

- x^{3} + 10 x^{2} - 32 x + 32 : - (x - 2) (x - 4)^{2}

- (x - 2) (x - 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = 2, x = 4

x^{5} - 7 x^{2} = 0

4 x^{4} + 25 x^{2} + 36 = 0

- 4 = x^{5} - 5 x

x, x^{3} + y^{3} = 2

x^{3} - 3 x^{2} + 3 x + 1 = 0

What are the solutions to the equation -x^3+10x^2-32x+32=0 ?
The solutions to the equation -x^3+10x^2-32x+32=0 are x=2,x=4
Find the zeros of -x^3+10x^2-32x+32=0
The zeros of -x^3+10x^2-32x+32=0 are x=2,x=4