What are the solutions to the equation x^4-4x^3+6x^2-4x+1=0 ?

The solutions to the equation x^4-4x^3+6x^2-4x+1=0 are x=1

Find the zeros of x^4-4x^3+6x^2-4x+1=0

The zeros of x^4-4x^3+6x^2-4x+1=0 are x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 = 0

x = 1

Solution steps

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 = 0

Factor

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 : (x - 1)^{4}

(x - 1)^{4} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0

Solve

x - 1 = 0 : x = 1

The solution is

x = 1

x^{4} + 5 x^{3} + 3 x^{2} - 9 x = 0

(6 x^{3}) x^{5} = 6 x (3 x^{5})

x^{3} - 2 x^{2} - 2 x - 1 = - 3

(x^{2} + 4)^{2} - 11 (x^{2} + 4) + 24 = 0

3 x^{3} - 4 x^{2} + 11 x + 10 = 0

What are the solutions to the equation x^4-4x^3+6x^2-4x+1=0 ?
The solutions to the equation x^4-4x^3+6x^2-4x+1=0 are x=1
Find the zeros of x^4-4x^3+6x^2-4x+1=0
The zeros of x^4-4x^3+6x^2-4x+1=0 are x=1