What are the solutions to the equation w^3=512 ?

The solutions to the equation w^3=512 are w=8,w=-4+4sqrt(3)i,w=-4-4sqrt(3)i

Find the zeros of w^3=512

The zeros of w^3=512 are w=8,w=-4+4sqrt(3)i,w=-4-4sqrt(3)i

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w^{3} = 512

w = 8, w = - 4 + 43 i, w = - 4 - 43 i

Solution steps

w^{3} = 512

For

x^{3} = f (a)

the solutions are

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

w = 3512, w = 3512 \frac{- 1 + 3 i}{2}, w = 3512 \frac{- 1 - 3 i}{2}

3512 = 8

Simplify

3512 \frac{- 1 + 3 i}{2} : - 4 + 43 i

Simplify

3512 \frac{- 1 - 3 i}{2} : - 4 - 43 i

w = 8, w = - 4 + 43 i, w = - 4 - 43 i

3 x^{4} - 2 x^{3} + 2 x^{2} - 8 x - 40 = 0

x, x^{1000} + y^{1000} = 5

x^{4} + 2 x^{3} - 3 x^{2} - 4 x + 4 = 0

x^{6} - x^{3} - 2 = 0

z^{4} + 2 z^{3} - 2 z - 1 = 0

What are the solutions to the equation w^3=512 ?
The solutions to the equation w^3=512 are w=8,w=-4+4sqrt(3)i,w=-4-4sqrt(3)i
Find the zeros of w^3=512
The zeros of w^3=512 are w=8,w=-4+4sqrt(3)i,w=-4-4sqrt(3)i