What are the solutions to the equation 9x^3-18x^2-4x+8=0 ?

The solutions to the equation 9x^3-18x^2-4x+8=0 are x=2,x=-2/3 ,x= 2/3

Find the zeros of 9x^3-18x^2-4x+8=0

The zeros of 9x^3-18x^2-4x+8=0 are x=2,x=-2/3 ,x= 2/3

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9 x^{3} - 18 x^{2} - 4 x + 8 = 0

x = 2, x = - \frac{2}{3}, x = \frac{2}{3}

Decimal Notation

x = 2, x = - 0.66666 \dots, x = 0.66666 \dots

Solution steps

9 x^{3} - 18 x^{2} - 4 x + 8 = 0

Factor

9 x^{3} - 18 x^{2} - 4 x + 8 : (x - 2) (3 x + 2) (3 x - 2)

(x - 2) (3 x + 2) (3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 3 x + 2 = 0 or 3 x - 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

The solutions are

x = 2, x = - \frac{2}{3}, x = \frac{2}{3}

x^{3} - 2 x^{2} - 3 x + 2 = 0

- 10 x^{4} - 27 x^{3} + 18 x^{2} = 0

r^{3} - 2 r^{2} - r + 2 = 0

- x^{3} + 2 x^{2} + 4 x - 8 = 0

9 = x^{3} + x

What are the solutions to the equation 9x^3-18x^2-4x+8=0 ?
The solutions to the equation 9x^3-18x^2-4x+8=0 are x=2,x=-2/3 ,x= 2/3
Find the zeros of 9x^3-18x^2-4x+8=0
The zeros of 9x^3-18x^2-4x+8=0 are x=2,x=-2/3 ,x= 2/3