What are the solutions to the equation x^3+4x^2-2x=0 ?

The solutions to the equation x^3+4x^2-2x=0 are x=0,x=-2+sqrt(6),x=-2-sqrt(6)

Find the zeros of x^3+4x^2-2x=0

The zeros of x^3+4x^2-2x=0 are x=0,x=-2+sqrt(6),x=-2-sqrt(6)

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x^{3} + 4 x^{2} - 2 x = 0

x = 0, x = - 2 + 6, x = - 2 - 6

Decimal Notation

x = 0, x = 0.44948 \dots, x = - 4.44948 \dots

Solution steps

x^{3} + 4 x^{2} - 2 x = 0

Factor

x^{3} + 4 x^{2} - 2 x : x (x^{2} + 4 x - 2)

x (x^{2} + 4 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 4 x - 2 = 0

Solve

x^{2} + 4 x - 2 = 0 : x = - 2 + 6, x = - 2 - 6

The solutions are

x = 0, x = - 2 + 6, x = - 2 - 6

x^{3} + x^{2} + 2 x - 3 = 0

x^{4} + 4 x - 1 = 0

64 = x^{3}

x^{2} + 4 x^{4} = 0

0 = x^{3} - 3 x

What are the solutions to the equation x^3+4x^2-2x=0 ?
The solutions to the equation x^3+4x^2-2x=0 are x=0,x=-2+sqrt(6),x=-2-sqrt(6)
Find the zeros of x^3+4x^2-2x=0
The zeros of x^3+4x^2-2x=0 are x=0,x=-2+sqrt(6),x=-2-sqrt(6)