What are the solutions to the equation (1+x^2)^2=0 ?

The solutions to the equation (1+x^2)^2=0 are x=i,x=-i

Find the zeros of (1+x^2)^2=0

The zeros of (1+x^2)^2=0 are x=i,x=-i

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(1 + x^{2})^{2} = 0

x = i, x = - i

Solution steps

(1 + x^{2})^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

1 + x^{2} = 0 : x = i, x = - i

The solutions are

x = i, x = - i

x^{2} - x^{3} = 0

g (n) = n^{3} - 5 n^{2}, g (- 4 n)

(x^{2} + x + 3) (x^{2} - x + 3) = 45

x^{4} + 9 x^{2} = 0

n^{3} + 2 n^{2} - 35 n = 0

What are the solutions to the equation (1+x^2)^2=0 ?
The solutions to the equation (1+x^2)^2=0 are x=i,x=-i
Find the zeros of (1+x^2)^2=0
The zeros of (1+x^2)^2=0 are x=i,x=-i