What are the solutions to the equation z^7=(-1+2j) ?

The solutions to the equation z^7=(-1+2j) are z=\sqrt[7]{-1+2j}

Find the zeros of z^7=(-1+2j)

The zeros of z^7=(-1+2j) are z=\sqrt[7]{-1+2j}

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z^{7} = (- 1 + 2 j)

Solution steps

z^{7} = (- 1 + 2 j)

Remove parentheses:

(a) = a

z^{7} = - 1 + 2 j

For

x^{n} = f (a)

, n is odd, the solution is

x^{4} + x^{2} = 12

2 x^{3} - 24 x^{2} + 70 x = 0

x^{4} - 12 x^{2} + 35 = 0

x^{3} - 3 x^{2} + x - 3 = x^{2} + 1

2 x^{3} - 30 x^{2} + 100 x = 0

What are the solutions to the equation z^7=(-1+2j) ?
The solutions to the equation z^7=(-1+2j) are z=\sqrt[7]{-1+2j}
Find the zeros of z^7=(-1+2j)
The zeros of z^7=(-1+2j) are z=\sqrt[7]{-1+2j}