What are the solutions to the equation (x-2)^2(x+1)^2=0 ?

The solutions to the equation (x-2)^2(x+1)^2=0 are x=2,x=-1

Find the zeros of (x-2)^2(x+1)^2=0

The zeros of (x-2)^2(x+1)^2=0 are x=2,x=-1

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(x - 2)^{2} (x + 1)^{2} = 0

x = 2, x = - 1

Solution steps

(x - 2)^{2} (x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 1 = 0 : x = - 1

The solutions are

x = 2, x = - 1

y, y^{3} = x^{2}

x^{5} = 25 x^{3}

x^{3} - 7 x^{2} + 16 x - 12 = 0

x^{6} + 56 x^{3} - 512 = 0

2 x^{3} - 3 x^{2} + 8 x - 12 = 0

What are the solutions to the equation (x-2)^2(x+1)^2=0 ?
The solutions to the equation (x-2)^2(x+1)^2=0 are x=2,x=-1
Find the zeros of (x-2)^2(x+1)^2=0
The zeros of (x-2)^2(x+1)^2=0 are x=2,x=-1