What are the solutions to the equation m^4-m^3-7m^2+m+6=0 ?

The solutions to the equation m^4-m^3-7m^2+m+6=0 are m=-1,m=1,m=-2,m=3

Find the zeros of m^4-m^3-7m^2+m+6=0

The zeros of m^4-m^3-7m^2+m+6=0 are m=-1,m=1,m=-2,m=3

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m^{4} - m^{3} - 7 m^{2} + m + 6 = 0

m = - 1, m = 1, m = - 2, m = 3

Solution steps

m^{4} - m^{3} - 7 m^{2} + m + 6 = 0

Factor

m^{4} - m^{3} - 7 m^{2} + m + 6 : (m + 1) (m - 1) (m + 2) (m - 3)

(m + 1) (m - 1) (m + 2) (m - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m + 1 = 0 or m - 1 = 0 or m + 2 = 0 or m - 3 = 0

Solve

m + 1 = 0 : m = - 1

Solve

m - 1 = 0 : m = 1

Solve

m + 2 = 0 : m = - 2

Solve

m - 3 = 0 : m = 3

The solutions are

m = - 1, m = 1, m = - 2, m = 3

12 k^{3} - 48 k^{2} + 12 k + 72 = 0

x - 3 x^{5} = \frac{1}{4}

x^{2} + x - 43 = 3 x^{4} - 1

2 x (3 x^{2} - 1) + 5 x = 16 x

x^{4} - 2 x^{3} = 16 + 8 x - 4 x^{3}

What are the solutions to the equation m^4-m^3-7m^2+m+6=0 ?
The solutions to the equation m^4-m^3-7m^2+m+6=0 are m=-1,m=1,m=-2,m=3
Find the zeros of m^4-m^3-7m^2+m+6=0
The zeros of m^4-m^3-7m^2+m+6=0 are m=-1,m=1,m=-2,m=3