What are the solutions to the equation x^3+3x^2-16x-48=0 ?

The solutions to the equation x^3+3x^2-16x-48=0 are x=-3,x=-4,x=4

Find the zeros of x^3+3x^2-16x-48=0

The zeros of x^3+3x^2-16x-48=0 are x=-3,x=-4,x=4

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x^{3} + 3 x^{2} - 16 x - 48 = 0

x = - 3, x = - 4, x = 4

Solution steps

x^{3} + 3 x^{2} - 16 x - 48 = 0

Factor

x^{3} + 3 x^{2} - 16 x - 48 : (x + 3) (x + 4) (x - 4)

(x + 3) (x + 4) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 4 = 0 or x - 4 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 4 = 0 : x = - 4

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 3, x = - 4, x = 4

2 x^{3} - 7 x^{2} + 9 = 0

x^{4} - 6 x^{3} + 11 x^{2} - 46 x + 170 = 0

12 x^{3} - 48 x^{2} + 12 x + 72 = 0

x^{6} - 9 x^{2} - 8 x^{4} = 0

2 x^{3} - 50 x = 0

What are the solutions to the equation x^3+3x^2-16x-48=0 ?
The solutions to the equation x^3+3x^2-16x-48=0 are x=-3,x=-4,x=4
Find the zeros of x^3+3x^2-16x-48=0
The zeros of x^3+3x^2-16x-48=0 are x=-3,x=-4,x=4