What are the solutions to the equation p(2p-5)^2-3(2p-5)=0 ?

The solutions to the equation p(2p-5)^2-3(2p-5)=0 are p=3,p= 5/2 ,p=-1/2

Find the zeros of p(2p-5)^2-3(2p-5)=0

The zeros of p(2p-5)^2-3(2p-5)=0 are p=3,p= 5/2 ,p=-1/2

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p (2 p - 5)^{2} - 3 (2 p - 5) = 0

p = 3, p = \frac{5}{2}, p = - \frac{1}{2}

Decimal Notation

p = 3, p = 2.5, p = - 0.5

Solution steps

p (2 p - 5)^{2} - 3 (2 p - 5) = 0

Factor

p (2 p - 5)^{2} - 3 (2 p - 5) : (p - 3) (2 p - 5) (2 p + 1)

(p - 3) (2 p - 5) (2 p + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

p - 3 = 0 or 2 p - 5 = 0 or 2 p + 1 = 0

Solve

p - 3 = 0 : p = 3

Solve

2 p - 5 = 0 : p = \frac{5}{2}

Solve

2 p + 1 = 0 : p = - \frac{1}{2}

The solutions are

p = 3, p = \frac{5}{2}, p = - \frac{1}{2}

x^{3} - 6 x^{2} - 15 x + 40 = 0

(12 x - 1) (6 x - 1) (4 x - 1) (3 x - 1) = 5

x^{3} - x = 4 x - x^{2}

12 y^{2} - 12 y^{3} = 2 y^{2} - 2 y

x^{3} + 4 x^{2} + x + 4 = 0

What are the solutions to the equation p(2p-5)^2-3(2p-5)=0 ?
The solutions to the equation p(2p-5)^2-3(2p-5)=0 are p=3,p= 5/2 ,p=-1/2
Find the zeros of p(2p-5)^2-3(2p-5)=0
The zeros of p(2p-5)^2-3(2p-5)=0 are p=3,p= 5/2 ,p=-1/2