What are the solutions to the equation (5-x)*(x^2-9)=0 ?

The solutions to the equation (5-x)*(x^2-9)=0 are x=5,x=-3,x=3

Find the zeros of (5-x)*(x^2-9)=0

The zeros of (5-x)*(x^2-9)=0 are x=5,x=-3,x=3

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(5 - x) \cdot (x^{2} - 9) = 0

x = 5, x = - 3, x = 3

Solution steps

(5 - x) (x^{2} - 9) = 0

Factor

(5 - x) (x^{2} - 9) : - (x - 5) (x + 3) (x - 3)

- (x - 5) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 5, x = - 3, x = 3

x^{3} - x^{2} + 4 x - 4 = 0

x^{4} - 14 x^{2} + 44 = 0

x^{4} - 14 x^{2} + 45 = 0

x^{3} + 8 x^{2} + 7 x = 0

x^{6} - 2 x^{3} + 4 = 16

What are the solutions to the equation (5-x)*(x^2-9)=0 ?
The solutions to the equation (5-x)*(x^2-9)=0 are x=5,x=-3,x=3
Find the zeros of (5-x)*(x^2-9)=0
The zeros of (5-x)*(x^2-9)=0 are x=5,x=-3,x=3