What are the solutions to the equation -x^3+7x^2-14x+8=0 ?

The solutions to the equation -x^3+7x^2-14x+8=0 are x=1,x=2,x=4

Find the zeros of -x^3+7x^2-14x+8=0

The zeros of -x^3+7x^2-14x+8=0 are x=1,x=2,x=4

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- x^{3} + 7 x^{2} - 14 x + 8 = 0

x = 1, x = 2, x = 4

Solution steps

- x^{3} + 7 x^{2} - 14 x + 8 = 0

Factor

- x^{3} + 7 x^{2} - 14 x + 8 : - (x - 1) (x - 2) (x - 4)

- (x - 1) (x - 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0 or x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = 1, x = 2, x = 4

z^{4} + 24 z^{2} - 25 = 0

- x^{3} + 11 x^{2} - 35 x + 25 = 0

4.5 t^{4} + 3.2 t^{3} + 25 t = 20

4 q^{5} - 25 q^{3} = 0

x^{4} = e^{6}

What are the solutions to the equation -x^3+7x^2-14x+8=0 ?
The solutions to the equation -x^3+7x^2-14x+8=0 are x=1,x=2,x=4
Find the zeros of -x^3+7x^2-14x+8=0
The zeros of -x^3+7x^2-14x+8=0 are x=1,x=2,x=4