What are the solutions to the equation 2x^4-7x^3+21x^2+17x-13=0 ?

The solutions to the equation 2x^4-7x^3+21x^2+17x-13=0 are x=-1,x= 1/2 ,x=2+3i,x=2-3i

Find the zeros of 2x^4-7x^3+21x^2+17x-13=0

The zeros of 2x^4-7x^3+21x^2+17x-13=0 are x=-1,x= 1/2 ,x=2+3i,x=2-3i

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2 x^{4} - 7 x^{3} + 21 x^{2} + 17 x - 13 = 0

x = - 1, x = \frac{1}{2}, x = 2 + 3 i, x = 2 - 3 i

Solution steps

2 x^{4} - 7 x^{3} + 21 x^{2} + 17 x - 13 = 0

Factor

2 x^{4} - 7 x^{3} + 21 x^{2} + 17 x - 13 : (x + 1) (2 x - 1) (x^{2} - 4 x + 13)

(x + 1) (2 x - 1) (x^{2} - 4 x + 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x - 1 = 0 or x^{2} - 4 x + 13 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x^{2} - 4 x + 13 = 0 : x = 2 + 3 i, x = 2 - 3 i

The solutions are

x = - 1, x = \frac{1}{2}, x = 2 + 3 i, x = 2 - 3 i

x^{3} - 28 x - 48 = 0

x, (x - 1) (x - 1) (x - 1) = y

b^{3} = 1000

12 x^{3} - 48 x = 0

x^{4} - x^{3} - 2 x^{2} + 6 x - 4 = 0

What are the solutions to the equation 2x^4-7x^3+21x^2+17x-13=0 ?
The solutions to the equation 2x^4-7x^3+21x^2+17x-13=0 are x=-1,x= 1/2 ,x=2+3i,x=2-3i
Find the zeros of 2x^4-7x^3+21x^2+17x-13=0
The zeros of 2x^4-7x^3+21x^2+17x-13=0 are x=-1,x= 1/2 ,x=2+3i,x=2-3i