What are the solutions to the equation x^3+3x^2+2x+6=0 ?

The solutions to the equation x^3+3x^2+2x+6=0 are x=-3,x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of x^3+3x^2+2x+6=0

The zeros of x^3+3x^2+2x+6=0 are x=-3,x=sqrt(2)i,x=-sqrt(2)i

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x^{3} + 3 x^{2} + 2 x + 6 = 0

x = - 3, x = 2 i, x = - 2 i

Solution steps

x^{3} + 3 x^{2} + 2 x + 6 = 0

Factor

x^{3} + 3 x^{2} + 2 x + 6 : (x + 3) (x^{2} + 2)

(x + 3) (x^{2} + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x^{2} + 2 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x^{2} + 2 = 0 : x = 2 i, x = - 2 i

The solutions are

x = - 3, x = 2 i, x = - 2 i

x^{4} = \frac{1}{16}

x^{4} + 2 x^{2} + x = 0

x^{3} - 8 x^{2} + 16 x = 0

22 - w^{3} = - 7

- x^{3} + 3 x^{2} + x - 3 = 0

What are the solutions to the equation x^3+3x^2+2x+6=0 ?
The solutions to the equation x^3+3x^2+2x+6=0 are x=-3,x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of x^3+3x^2+2x+6=0
The zeros of x^3+3x^2+2x+6=0 are x=-3,x=sqrt(2)i,x=-sqrt(2)i