What are the solutions to the equation x^3+3x^2-6x-18=0 ?

The solutions to the equation x^3+3x^2-6x-18=0 are x=-3,x=-sqrt(6),x=sqrt(6)

Find the zeros of x^3+3x^2-6x-18=0

The zeros of x^3+3x^2-6x-18=0 are x=-3,x=-sqrt(6),x=sqrt(6)

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x^{3} + 3 x^{2} - 6 x - 18 = 0

x = - 3, x = - 6, x = 6

Decimal Notation

x = - 3, x = - 2.44948 \dots, x = 2.44948 \dots

Solution steps

x^{3} + 3 x^{2} - 6 x - 18 = 0

Factor

x^{3} + 3 x^{2} - 6 x - 18 : (x + 3) (x + 6) (x - 6)

(x + 3) (x + 6) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 6 = 0 or x - 6 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

The solutions are

x = - 3, x = - 6, x = 6

8 y^{3} - 27 = 0

x^{3} - 8 x^{2} - x + 8 = 0

3 x^{3} - 9 x^{2} + 3 x - 9 = 0

x^{3} + 3 x^{2} + 1 = 0

x, x^{4} - 2 x^{2} - 3 = 0

What are the solutions to the equation x^3+3x^2-6x-18=0 ?
The solutions to the equation x^3+3x^2-6x-18=0 are x=-3,x=-sqrt(6),x=sqrt(6)
Find the zeros of x^3+3x^2-6x-18=0
The zeros of x^3+3x^2-6x-18=0 are x=-3,x=-sqrt(6),x=sqrt(6)