What are the solutions to the equation x^3-x^2=4 ?

The solutions to the equation x^3-x^2=4 are x=2,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

Find the zeros of x^3-x^2=4

The zeros of x^3-x^2=4 are x=2,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - x^{2} = 4

x = 2, x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

Solution steps

x^{3} - x^{2} = 4

Move

4

to the left side

x^{3} - x^{2} - 4 = 0

Factor

x^{3} - x^{2} - 4 : (x - 2) (x^{2} + x + 2)

(x - 2) (x^{2} + x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + x + 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + x + 2 = 0 : x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

The solutions are

x = 2, x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

5 x^{3} + 6 x^{2} - 18 x + 5 = 0

x^{4} - 2 x^{2} - 24 = 0

- x^{3} - x^{2} + x + 1 = 0

x^{3} - 6 x^{2} - 27 x = 0

x^{3} = 0.008

What are the solutions to the equation x^3-x^2=4 ?
The solutions to the equation x^3-x^2=4 are x=2,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2
Find the zeros of x^3-x^2=4
The zeros of x^3-x^2=4 are x=2,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2