What are the solutions to the equation 3t^4-t^2-2=0 ?

The solutions to the equation 3t^4-t^2-2=0 are t=1,t=-1,t=sqrt(2/3)i,t=-sqrt(2/3)i

Find the zeros of 3t^4-t^2-2=0

The zeros of 3t^4-t^2-2=0 are t=1,t=-1,t=sqrt(2/3)i,t=-sqrt(2/3)i

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3 t^{4} - t^{2} - 2 = 0

t = 1, t = - 1, t = \frac{2}{3} i, t = - \frac{2}{3} i

Solution steps

3 t^{4} - t^{2} - 2 = 0

Rewrite the equation with

u = t^{2}

and

u^{2} = t^{4}

3 u^{2} - u - 2 = 0

Solve

3 u^{2} - u - 2 = 0 : u = 1, u = - \frac{2}{3}

u = 1, u = - \frac{2}{3}

Substitute back

u = t^{2},

solve for

t

Solve

t^{2} = 1 : t = 1, t = - 1

Solve

t^{2} = - \frac{2}{3} : t = \frac{2}{3} i, t = - \frac{2}{3} i

The solutions are

t = 1, t = - 1, t = \frac{2}{3} i, t = - \frac{2}{3} i

x^{3} + x^{2} = 2 x

x^{4} - 13 x^{2} + 12 = 0

x, x^{4} + y^{4} = 1

2 x^{3} = 18 x

(5 - x) (x^{2} - 9) = 0

What are the solutions to the equation 3t^4-t^2-2=0 ?
The solutions to the equation 3t^4-t^2-2=0 are t=1,t=-1,t=sqrt(2/3)i,t=-sqrt(2/3)i
Find the zeros of 3t^4-t^2-2=0
The zeros of 3t^4-t^2-2=0 are t=1,t=-1,t=sqrt(2/3)i,t=-sqrt(2/3)i