What are the solutions to the equation (x^3-1)=0 ?

The solutions to the equation (x^3-1)=0 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

Find the zeros of (x^3-1)=0

The zeros of (x^3-1)=0 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

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(x^{3} - 1) = 0

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Solution steps

(x^{3} - 1) = 0

x^{3} - 1 = 0

Move

1

to the right side

x^{3} = 1

For

x^{3} = f (a)

the solutions are

x = 1, x = \frac{- 1 + 3 i}{2}, x = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

z^{3} = 216

x^{3} - 13 x^{2} + 40 x = 0

16 x^{4} - 8 x^{2} + 1 = 0

4 x^{3} - 36 x^{2} + 96 x - 64 = 0

6 x^{4} = - 96 x^{2}

What are the solutions to the equation (x^3-1)=0 ?
The solutions to the equation (x^3-1)=0 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i
Find the zeros of (x^3-1)=0
The zeros of (x^3-1)=0 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i