What are the solutions to the equation 3(x-1)(x+2)(x-4)=0 ?

The solutions to the equation 3(x-1)(x+2)(x-4)=0 are x=1,x=-2,x=4

Find the zeros of 3(x-1)(x+2)(x-4)=0

The zeros of 3(x-1)(x+2)(x-4)=0 are x=1,x=-2,x=4

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3 (x - 1) (x + 2) (x - 4) = 0

x = 1, x = - 2, x = 4

Solution steps

3 (x - 1) (x + 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = 1, x = - 2, x = 4

x^{4} - x^{3} + x = 1

- 2 x (x^{2} - 10) (x^{2} + 4) = 0

y^{4} + y^{2} - 2 = 0

- x^{3} - 2 x^{2} = 0

x^{3} - 7 x^{2} + x - 7 = x^{2} + 1

What are the solutions to the equation 3(x-1)(x+2)(x-4)=0 ?
The solutions to the equation 3(x-1)(x+2)(x-4)=0 are x=1,x=-2,x=4
Find the zeros of 3(x-1)(x+2)(x-4)=0
The zeros of 3(x-1)(x+2)(x-4)=0 are x=1,x=-2,x=4