What are the solutions to the equation w^3=i ?

The solutions to the equation w^3=i are w=(sqrt(3))/2+i 1/2 ,w=-(sqrt(3))/2+i 1/2 ,w=-i

Find the zeros of w^3=i

The zeros of w^3=i are w=(sqrt(3))/2+i 1/2 ,w=-(sqrt(3))/2+i 1/2 ,w=-i

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w^{3} = i

w = \frac{3}{2} + i \frac{1}{2}, w = - \frac{3}{2} + i \frac{1}{2}, w = - i

Solution steps

w^{3} = i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 3, a = i

∣ a ∣ = 1

ar g (a) = \frac{π}{2}

Simplify

w = \frac{3}{2} + i \frac{1}{2}, w = - \frac{3}{2} + i \frac{1}{2}, w = - i

z^{3} = \frac{i}{8}

x^{2} (x - 6) = 0

z^{4} = 1 + i

5 x^{3} - 6 x^{2} - 7 = 0

0 = x^{4} - 2 x^{2} - 8

What are the solutions to the equation w^3=i ?
The solutions to the equation w^3=i are w=(sqrt(3))/2+i 1/2 ,w=-(sqrt(3))/2+i 1/2 ,w=-i
Find the zeros of w^3=i
The zeros of w^3=i are w=(sqrt(3))/2+i 1/2 ,w=-(sqrt(3))/2+i 1/2 ,w=-i