What are the solutions to the equation 3x^3-7x^2+3x-7=0 ?

The solutions to the equation 3x^3-7x^2+3x-7=0 are x= 7/3 ,x=i,x=-i

Find the zeros of 3x^3-7x^2+3x-7=0

The zeros of 3x^3-7x^2+3x-7=0 are x= 7/3 ,x=i,x=-i

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3 x^{3} - 7 x^{2} + 3 x - 7 = 0

x = \frac{7}{3}, x = i, x = - i

Solution steps

3 x^{3} - 7 x^{2} + 3 x - 7 = 0

Factor

3 x^{3} - 7 x^{2} + 3 x - 7 : (3 x - 7) (x^{2} + 1)

(3 x - 7) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 7 = 0 or x^{2} + 1 = 0

Solve

3 x - 7 = 0 : x = \frac{7}{3}

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = \frac{7}{3}, x = i, x = - i

z^{4} = 2 z

457551.55 = 200000 (1 + x)^{5}

(x + 3) (x^{2} - 2) = x + 3

x^{4} + 64 x = 0

4 x = x (2 x - 4)^{2}

What are the solutions to the equation 3x^3-7x^2+3x-7=0 ?
The solutions to the equation 3x^3-7x^2+3x-7=0 are x= 7/3 ,x=i,x=-i
Find the zeros of 3x^3-7x^2+3x-7=0
The zeros of 3x^3-7x^2+3x-7=0 are x= 7/3 ,x=i,x=-i