What are the solutions to the equation (x-1)^3+2=0 ?

The solutions to the equation (x-1)^3+2=0 are x=-\sqrt[3]{2}+1

Find the zeros of (x-1)^3+2=0

The zeros of (x-1)^3+2=0 are x=-\sqrt[3]{2}+1

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(x - 1)^{3} + 2 = 0

Decimal Notation

x = - 0.25992 \dots

Solution steps

(x - 1)^{3} + 2 = 0

Move

2

to the right side

(x - 1)^{3} = - 2

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

8 x^{4} - 18 x^{2} = 0

2 x^{4} + x^{2} - 3 = 0

x^{3} + 3 x^{2} - 24 x + 1 = 0

x, x^{7} + y^{7} = 128

50 x = 2 x^{3}

What are the solutions to the equation (x-1)^3+2=0 ?
The solutions to the equation (x-1)^3+2=0 are x=-\sqrt[3]{2}+1
Find the zeros of (x-1)^3+2=0
The zeros of (x-1)^3+2=0 are x=-\sqrt[3]{2}+1