What are the solutions to the equation x^4+27x=0 ?

The solutions to the equation x^4+27x=0 are x=0,x=-3,x= 3/2-(3sqrt(3))/2 i,x= 3/2+(3sqrt(3))/2 i

Find the zeros of x^4+27x=0

The zeros of x^4+27x=0 are x=0,x=-3,x= 3/2-(3sqrt(3))/2 i,x= 3/2+(3sqrt(3))/2 i

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x^{4} + 27 x = 0

x = 0, x = - 3, x = \frac{3}{2} - \frac{3 3}{2} i, x = \frac{3}{2} + \frac{3 3}{2} i

Solution steps

x^{4} + 27 x = 0

Factor

x^{4} + 27 x : x (x^{3} + 27)

x (x^{3} + 27) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{3} + 27 = 0

Solve

x^{3} + 27 = 0 : x = - 3, x = \frac{3}{2} - \frac{3 3}{2} i, x = \frac{3}{2} + \frac{3 3}{2} i

The solutions are

x = 0, x = - 3, x = \frac{3}{2} - \frac{3 3}{2} i, x = \frac{3}{2} + \frac{3 3}{2} i

x^{4} - 4 x^{3} + 15 x^{2} - 4 x + 14 = 0

(x) (2 x)^{2} = 3.2 \cdot 1 0^{- 8}

x^{4} + 6 x^{2} + 5 = 0

x, x^{4} - 5 x^{2} + 4 = 0

(x + 2) (x^{2} - 2 x + 4) = 0

What are the solutions to the equation x^4+27x=0 ?
The solutions to the equation x^4+27x=0 are x=0,x=-3,x= 3/2-(3sqrt(3))/2 i,x= 3/2+(3sqrt(3))/2 i
Find the zeros of x^4+27x=0
The zeros of x^4+27x=0 are x=0,x=-3,x= 3/2-(3sqrt(3))/2 i,x= 3/2+(3sqrt(3))/2 i