What are the solutions to the equation (x^2-3x+1)^6=1 ?

The solutions to the equation (x^2-3x+1)^6=1 are x=3,x=0,x=2,x=1

Find the zeros of (x^2-3x+1)^6=1

The zeros of (x^2-3x+1)^6=1 are x=3,x=0,x=2,x=1

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(x^{2} - 3 x + 1)^{6} = 1

x = 3, x = 0, x = 2, x = 1

Solution steps

(x^{2} - 3 x + 1)^{6} = 1

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 3, x = 0, x = 2, x = 1

x^{4} + x^{2} - 42 = 0

x, 4 x^{3} - 4 y = 0

- 4 x^{3} = 36 x

z^{8} = 1

x^{3} - 8 x^{2} + 25 x - 26 = 0

What are the solutions to the equation (x^2-3x+1)^6=1 ?
The solutions to the equation (x^2-3x+1)^6=1 are x=3,x=0,x=2,x=1
Find the zeros of (x^2-3x+1)^6=1
The zeros of (x^2-3x+1)^6=1 are x=3,x=0,x=2,x=1